Ich versuche, Bilder von der Website herunterzuladen. Der von mir verwendete Code funktioniert gut, solange das Bild verfügbar ist. Wenn das Bild nicht verfügbar ist, wird ein Problem erstellt. Wie kann ich die Verfügbarkeit des Bildes überprüfen?
Code:
Methode 1:
WebRequest requestPic = WebRequest.Create(imageUrl);
WebResponse responsePic = requestPic.GetResponse();
Image webImage = Image.FromStream(responsePic.GetResponseStream()); // Error
webImage.Save("D:\\Images\\Book\\" + fileName + ".jpg");
Methode 2:
WebClient client = new WebClient();
Stream stream = client.OpenRead(imageUrl);
bitmap = new Bitmap(stream); // Error : Parameter is not valid.
stream.Flush();
stream.Close();
client.dispose();
if (bitmap != null)
{
bitmap.Save("D:\\Images\\" + fileName + ".jpg");
}
Bearbeiten:
Stream hat die folgenden Aussagen:
Length '((System.Net.ConnectStream)(str)).Length' threw an exception of type 'System.NotSupportedException' long {System.NotSupportedException}
Position '((System.Net.ConnectStream)(str)).Position' threw an exception of type 'System.NotSupportedException' long {System.NotSupportedException}
ReadTimeout 300000 int
WriteTimeout 300000 int
Es ist nicht erforderlich, Bildklassen einzubeziehen. Sie können einfach WebClient.DownloadFile
aufrufen:
string localFilename = @"c:\localpath\tofile.jpg";
using(WebClient client = new WebClient())
{
client.DownloadFile("http://www.example.com/image.jpg", localFilename);
}
Update
Da Sie prüfen möchten, ob die Datei vorhanden ist, und die Datei ggf. herunterladen, sollten Sie dies in derselben Anfrage tun. Hier ist eine Methode, die das tut:
private static void DownloadRemoteImageFile(string uri, string fileName)
{
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri);
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
// Check that the remote file was found. The ContentType
// check is performed since a request for a non-existent
// image file might be redirected to a 404-page, which would
// yield the StatusCode "OK", even though the image was not
// found.
if ((response.StatusCode == HttpStatusCode.OK ||
response.StatusCode == HttpStatusCode.Moved ||
response.StatusCode == HttpStatusCode.Redirect) &&
response.ContentType.StartsWith("image",StringComparison.OrdinalIgnoreCase))
{
// if the remote file was found, download oit
using (Stream inputStream = response.GetResponseStream())
using (Stream outputStream = File.OpenWrite(fileName))
{
byte[] buffer = new byte[4096];
int bytesRead;
do
{
bytesRead = inputStream.Read(buffer, 0, buffer.Length);
outputStream.Write(buffer, 0, bytesRead);
} while (bytesRead != 0);
}
}
}
Kurz gesagt, es wird eine Anforderung für die Datei gestellt, und es wird überprüft, ob der Antwortcode eine der Variablen OK
, Moved
oder Redirect
und auchist _, dass die ContentType
ein Bild ist. Wenn diese Bedingungen erfüllt sind, wird die Datei heruntergeladen.
Ich habe Fredriks Code oben in einem Projekt mit einigen geringfügigen Änderungen verwendet.
private static bool DownloadRemoteImageFile(string uri, string fileName)
{
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri);
HttpWebResponse response;
try
{
response = (HttpWebResponse)request.GetResponse();
}
catch (Exception)
{
return false;
}
// Check that the remote file was found. The ContentType
// check is performed since a request for a non-existent
// image file might be redirected to a 404-page, which would
// yield the StatusCode "OK", even though the image was not
// found.
if ((response.StatusCode == HttpStatusCode.OK ||
response.StatusCode == HttpStatusCode.Moved ||
response.StatusCode == HttpStatusCode.Redirect) &&
response.ContentType.StartsWith("image", StringComparison.OrdinalIgnoreCase))
{
// if the remote file was found, download it
using (Stream inputStream = response.GetResponseStream())
using (Stream outputStream = File.OpenWrite(fileName))
{
byte[] buffer = new byte[4096];
int bytesRead;
do
{
bytesRead = inputStream.Read(buffer, 0, buffer.Length);
outputStream.Write(buffer, 0, bytesRead);
} while (bytesRead != 0);
}
return true;
}
else
return false;
}
Hauptänderungen sind:
Die DownloadData-Methode kann auch verwendet werden
private byte[] GetImage(string iconPath)
{
using (WebClient client = new WebClient())
{
byte[] pic = client.DownloadData(iconPath);
//string checkPath = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments) [email protected]"\1.png";
//File.WriteAllBytes(checkPath, pic);
return pic;
}
}
private static void DownloadRemoteImageFile(string uri, string fileName)
{
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri);
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
if ((response.StatusCode == HttpStatusCode.OK ||
response.StatusCode == HttpStatusCode.Moved ||
response.StatusCode == HttpStatusCode.Redirect) &&
response.ContentType.StartsWith("image", StringComparison.OrdinalIgnoreCase))
{
using (Stream inputStream = response.GetResponseStream())
using (Stream outputStream = File.OpenWrite(fileName))
{
byte[] buffer = new byte[4096];
int bytesRead;
do
{
bytesRead = inputStream.Read(buffer, 0, buffer.Length);
outputStream.Write(buffer, 0, bytesRead);
} while (bytesRead != 0);
}
}
}
Es empfiehlt sich, ein Bild vom Server oder von der Website herunterzuladen und lokal zu speichern.
WebClient client=new Webclient();
client.DownloadFile("WebSite URL","C:\\....image.jpg");
client.Dispose();