web-dev-qa-db-ger.com

Ein einfaches http post-Beispiel in Objective-C?

Ich habe eine PHP-Webseite, für die ein Login erforderlich ist (Benutzer-ID und Kennwort). Ich muss den Benutzer die Informationen in die App eingeben. Aber ich brauche ein Beispiel, wie man eine POST Anfrage an eine Website stellt. Das Apple-Beispiel auf der Support-Site ist ziemlich kompliziert, wenn Sie ein Bild hochladen möchten. Meines sollte einfacher sein.

Alex

51
Alex van Es

Das habe ich kürzlich benutzt und es hat gut funktioniert für mich:

NSString *post = @"key1=val1&key2=val2";
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];

NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
[request setURL:[NSURL URLWithString:@"http://www.nowhere.com/sendFormHere.php"]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];

Ursprünglich aus http://deusty.blogspot.com/2006/11/sending-http-get-and-post-from-cocoa.html entnommen, aber das Blog scheint nicht mehr zu existieren.

113
fresskoma

Von der offiziellen Website von Apple

// In body data for the 'application/x-www-form-urlencoded' content type,
// form fields are separated by an ampersand. Note the absence of a
// leading ampersand.
NSString *bodyData = @"name=Jane+Doe&address=123+Main+St";

NSMutableURLRequest *postRequest = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"https://www.Apple.com"]];

// Set the request's content type to application/x-www-form-urlencoded
[postRequest setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

// Designate the request a POST request and specify its body data
[postRequest setHTTPMethod:@"POST"];
[postRequest setHTTPBody:[NSData dataWithBytes:[bodyData UTF8String] length:strlen([bodyData UTF8String])]];

// Initialize the NSURLConnection and proceed as described in
// Retrieving the Contents of a URL

Von: Code mit Chris

    // Create the request.
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://google.com"]];

// Specify that it will be a POST request
request.HTTPMethod = @"POST";

// This is how we set header fields
[request setValue:@"application/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];

// Convert your data and set your request's HTTPBody property
NSString *stringData = @"some data";
NSData *requestBodyData = [stringData dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPBody = requestBodyData;

// Create url connection and fire request
NSURLConnection *conn = [[NSURLConnection alloc] initWithRequest:request delegate:self];
13
Naeem

ASIHTTPRequest macht die Netzwerkkommunikation wirklich einfach

ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];
[request addPostValue:@"Ben" forKey:@"names"];
[request addPostValue:@"George" forKey:@"names"];
[request addFile:@"/Users/ben/Desktop/ben.jpg" forKey:@"photos"];
[request addData:imageData withFileName:@"george.jpg" andContentType:@"image/jpeg" forKey:@"photos"];
12
vikingosegundo

Sie können zwei Optionen verwenden:

Verwendung von NSURLConnection:

NSURL* URL = [NSURL URLWithString:@"http://www.example.com/path"];
NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:URL];
request.HTTPMethod = @"POST";
// Form URL-Encoded Body

NSDictionary* bodyParameters = @{
    @"username": @"reallyrambody",
    @"password": @"123456"
};
request.HTTPBody = [NSStringFromQueryParameters(bodyParameters) dataUsingEncoding:NSUTF8StringEncoding];

// Connection

NSURLConnection* connection = [NSURLConnection connectionWithRequest:request delegate:nil];
[connection start];

/*
 * Utils: Add this section before your class implementation
 */

/**
 This creates a new query parameters string from the given NSDictionary. For
 example, if the input is @{@"day":@"Tuesday", @"month":@"January"}, the output
 string will be @"day=Tuesday&month=January".
 @param queryParameters The input dictionary.
 @return The created parameters string.
*/
static NSString* NSStringFromQueryParameters(NSDictionary* queryParameters)
{
    NSMutableArray* parts = [NSMutableArray array];
    [queryParameters enumerateKeysAndObjectsUsingBlock:^(id key, id value, BOOL *stop) {
        NSString *part = [NSString stringWithFormat: @"%@=%@",
            [key stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding],
            [value stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding]
        ];
        [parts addObject:part];
    }];
    return [parts componentsJoinedByString: @"&"];
}

/**
 Creates a new URL by adding the given query parameters.
 @param URL The input URL.
 @param queryParameters The query parameter dictionary to add.
 @return A new NSURL.
*/
static NSURL* NSURLByAppendingQueryParameters(NSURL* URL, NSDictionary* queryParameters)
{
    NSString* URLString = [NSString stringWithFormat:@"%@?%@",
        [URL absoluteString],
        NSStringFromQueryParameters(queryParameters)
    ];
    return [NSURL URLWithString:URLString];
}

NSURLSession verwenden

- (void)sendRequest:(id)sender
{
    /* Configure session, choose between:
       * defaultSessionConfiguration
       * ephemeralSessionConfiguration
       * backgroundSessionConfigurationWithIdentifier:
     And set session-wide properties, such as: HTTPAdditionalHeaders,
     HTTPCookieAcceptPolicy, requestCachePolicy or timeoutIntervalForRequest.
     */
    NSURLSessionConfiguration* sessionConfig = [NSURLSessionConfiguration defaultSessionConfiguration];

    /* Create session, and optionally set a NSURLSessionDelegate. */
    NSURLSession* session = [NSURLSession sessionWithConfiguration:sessionConfig delegate:nil delegateQueue:nil];

    /* Create the Request:
       Token Duplicate (POST http://www.example.com/path)
     */

    NSURL* URL = [NSURL URLWithString:@"http://www.example.com/path"];
    NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:URL];
    request.HTTPMethod = @"POST";

    // Form URL-Encoded Body

    NSDictionary* bodyParameters = @{
        @"username": @"reallyram",
        @"password": @"123456"
    };
    request.HTTPBody = [NSStringFromQueryParameters(bodyParameters) dataUsingEncoding:NSUTF8StringEncoding];

    /* Start a new Task */
    NSURLSessionDataTask* task = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
        if (error == nil) {
            // Success
            NSLog(@"URL Session Task Succeeded: HTTP %ld", ((NSHTTPURLResponse*)response).statusCode);
        }
        else {
            // Failure
            NSLog(@"URL Session Task Failed: %@", [error localizedDescription]);
        }
    }];
    [task resume];
}

/*
 * Utils: Add this section before your class implementation
 */

/**
 This creates a new query parameters string from the given NSDictionary. For
 example, if the input is @{@"day":@"Tuesday", @"month":@"January"}, the output
 string will be @"day=Tuesday&month=January".
 @param queryParameters The input dictionary.
 @return The created parameters string.
*/
static NSString* NSStringFromQueryParameters(NSDictionary* queryParameters)
{
    NSMutableArray* parts = [NSMutableArray array];
    [queryParameters enumerateKeysAndObjectsUsingBlock:^(id key, id value, BOOL *stop) {
        NSString *part = [NSString stringWithFormat: @"%@=%@",
            [key stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding],
            [value stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding]
        ];
        [parts addObject:part];
    }];
    return [parts componentsJoinedByString: @"&"];
}

/**
 Creates a new URL by adding the given query parameters.
 @param URL The input URL.
 @param queryParameters The query parameter dictionary to add.
 @return A new NSURL.
*/
static NSURL* NSURLByAppendingQueryParameters(NSURL* URL, NSDictionary* queryParameters)
{
    NSString* URLString = [NSString stringWithFormat:@"%@?%@",
        [URL absoluteString],
        NSStringFromQueryParameters(queryParameters)
    ];
    return [NSURL URLWithString:URLString];
}
4
Ram Suthar
 NSMutableDictionary *contentDictionary = [[NSMutableDictionary alloc]init];
[contentDictionary setValue:@"name" forKey:@"email"];
[contentDictionary setValue:@"name" forKey:@"username"];
[contentDictionary setValue:@"name" forKey:@"password"];
[contentDictionary setValue:@"name" forKey:@"firstName"];
[contentDictionary setValue:@"name" forKey:@"lastName"];

NSData *data = [NSJSONSerialization dataWithJSONObject:contentDictionary options:NSJSONWritingPrettyPrinted error:nil];
NSString *jsonStr = [[NSString alloc] initWithData:data
                                          encoding:NSUTF8StringEncoding];
NSLog(@"%@",jsonStr);

NSString *urlString = [NSString stringWithFormat:@"http://testgcride.com:8081/v1/users"];
NSURL *url = [NSURL URLWithString:urlString];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPMethod:@"POST"];
   [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];


[request setHTTPBody:[jsonStr dataUsingEncoding:NSUTF8StringEncoding]];

AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
[manager.requestSerializer setAuthorizationHeaderFieldWithUsername:@"moinsam" password:@"cheese"];
manager.requestSerializer = [AFJSONRequestSerializer serializer];

AFHTTPRequestOperation *operation = [manager HTTPRequestOperationWithRequest:request success:<block> failure:<block>];
2
Chayon Ahmed

Ich bin ein Anfänger in iPhone-Apps und habe immer noch ein Problem, obwohl ich die obigen Ratschläge befolgt habe. Es sieht so aus, als ob POST -Variablen nicht von meinem Server empfangen werden - nicht sicher, ob sie von PHP- oder Ziel-C-Code stammen.

der objektive-c-Teil (codiert nach Chris 'Protokollmethode)

// Create the request.
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://example.php"]];

// Specify that it will be a POST request
request.HTTPMethod = @"POST";

// This is how we set header fields
[request setValue:@"application/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];

// Convert your data and set your request's HTTPBody property
NSString *stringData = [NSString stringWithFormat:@"user_name=%@&password=%@", self.userNameField.text , self.passwordTextField.text];
NSData *requestBodyData = [stringData dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPBody = requestBodyData;

// Create url connection and fire request
//NSURLConnection *conn = [[NSURLConnection alloc] initWithRequest:request delegate:self];
NSData *response = [NSURLConnection sendSynchronousRequest:request
                                         returningResponse:nil error:nil];

NSLog(@"Response: %@",[[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]);

Unter dem PHP-Teil:

if (isset($_POST['user_name'],$_POST['password'])) 

{

// Create connection
$con2=mysqli_connect($servername, $username, $password, $dbname);
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
else 
{
// retrieve POST vars
$username = $_POST['user_name'];
$password = $_POST['password'];

$sql = "INSERT INTO myTable (user_name, password) VALUES ('$username',   '$password')";
$retval = mysqli_query( $sql, $con2 );
if(! $retval )
{
die('Could not enter data: ' . mysql_error());
}
echo "Entered data successfully\n";

mysqli_close($con2);

}
}
else
{
echo "No data input in php";
}

Ich habe die letzten Tage hier festgehalten.

2
jules

Hier füge ich Beispielcode für http post print response hinzu und parst als JSON, wenn möglich. Er wird alles asynchron verarbeiten, so dass Ihre GUI einfach aktualisiert wird und nicht einfriert.

//POST DATA
NSString *theBody = [NSString stringWithFormat:@"parameter=%@",YOUR_VAR_HERE];
NSData *bodyData = [theBody dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
//URL CONFIG
NSString *serverURL = @"https://your-website-here.com";
NSString *downloadUrl = [NSString stringWithFormat:@"%@/your-friendly-url-here/json",serverURL];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString: downloadUrl]];
//POST DATA SETUP
[request setHTTPMethod:@"POST"];
[request setHTTPBody:bodyData];
//DEBUG MESSAGE
NSLog(@"Trying to call ws %@",downloadUrl);
//EXEC CALL
[NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue currentQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
    if (error) {
        NSLog(@"Download Error:%@",error.description);
    }
    if (data) {

        //
        // THIS CODE IS FOR PRINTING THE RESPONSE
        //
        NSString *returnString = [[NSString alloc] initWithData:data encoding: NSUTF8StringEncoding];
        NSLog(@"Response:%@",returnString);

        //PARSE JSON RESPONSE
        NSDictionary *json_response = [NSJSONSerialization JSONObjectWithData:data
                                                                      options:0
                                                                        error:NULL];

        if ( json_response ) {
            if ( [json_response isKindOfClass:[NSDictionary class]] ) {
                // do dictionary things
                for ( NSString *key in [json_response allKeys] ) {
                    NSLog(@"%@: %@", key, json_response[key]);
                }
            }
            else if ( [json_response isKindOfClass:[NSArray class]] ) {
                NSLog(@"%@",json_response);
            }
        }
        else {
            NSLog(@"Error serializing JSON: %@", error);
            NSLog(@"RAW RESPONSE: %@",data);
            NSString *returnString2 = [[NSString alloc] initWithData:data encoding: NSUTF8StringEncoding];
            NSLog(@"Response:%@",returnString2);
        }
    }
}];

Hoffe das hilft!

0
d1jhoni1b

Vielen Dank es hat funktioniert, bitte beachten Sie, dass ich einen Tippfehler in PHP gemacht habe, da es mysqli_query sein sollte ($ con2, $ sql)

0
jules